Club Filter

In mathematics, particularly in set theory, if \kappa is a regular uncountable cardinal then \operatorname{club}(\kappa), the filter of all sets containing a club subset of \kappa, is a \kappa-complete filter closed under diagonal intersection called the club filter. To see that this is a filter, note that \kappa\in\operatorname{club}(\kappa) since it is thus both closed and unbounded (see club set). If x\in\operatorname{club}(\kappa) then any subset of \kappa containing x is also in \operatorname{club}(\kappa), since x, and therefore anything containing it, contains a club set. It is a \kappa-complete filter because the intersection of fewer than \kappa club sets is a club set. To see this, suppose \langle C_i\rangle_{i<\alpha} is a sequence of club sets where \alpha<\kappa. Obviously C=\bigcap C_i is closed, since any sequence which appears in C appears in every C_i, and therefore its limit is also in every C_i. To show that it is unbounded, take some \beta<\kappa. Let \langle \beta_{1,i}\rangle be an increasing sequence with \beta_{1,1}>\beta and \beta_{1,i}\in C_i for every i<\alpha. Such a sequence can be constructed, since every C_i is unbounded. Since \alpha<\kappa and \kappa is regular, the limit of this sequence is less than \kappa. We call it \beta_2, and define a new sequence \langle\beta_{2,i}\rangle similar to the previous sequence. We can repeat this process, getting a sequence of sequences \langle\beta_{j,i}\rangle where each element of a sequence is greater than every member of the previous sequences. Then for each i<\alpha, \langle\beta_{j,i}\rangle is an increasing sequence contained in C_i, and all these sequences have the same limit (the limit of \langle\beta_{j,i}\rangle). This limit is then contained in every C_i, and therefore C, and is greater than \beta. To see that \operatorname{club}(\kappa) is closed under diagonal intersection, let \langle C_i\rangle, i<\kappa be a sequence, and let C=\Delta_{i<\kappa} C_i. Since the diagonal intersection contains the intersection, obviously C is unbounded. Then suppose S\subseteq C and \sup(S\cap\alpha)=\alpha. Then S\subseteq C_\beta for every \beta\geq\alpha, and since each C_\beta is closed, \alpha\in C_\beta, so \alpha\in C.

 

<< PreviousWord BrowserNext >>
geography of london
diagonal intersection
americorps florida state parks
in dreams (song)
auld mortality
actfl proficiency guidelines
sylvan goldman
bird people
infinite bounce
complex cloth
heterotopia
victor laloux
insignificance (film)
hinkle fieldhouse
hualahuises
jean boudin
huping hu
castner process
the cutting edge
expansion chamber
edward j. nanson
mauro camoranesi
crew dog
lake chaparral
irish twenty pence (decimal coin)
randall ford
kingdoms of han dynasty
military communication of feudal japan
canadian mennonite university
michael donohoe
tim cahill
frank peter zimmermann
contemplative images
jessica einhorn
carlo michelstaedter
18 kingdoms
golden gate national cemetery
april fools' jokes in the mainstream media
estonian parliamentary election, 1992
list of counts of comminges
oodbms
via (geomancy)
synagogue of rome
cauda draconis (geomancy)