Circular Orbit

In astrodynamics or celestial mechanics a circular orbit is an elliptic orbit with the eccentricity equal to 0.
   

Velocity

Under standard assumptions the orbital velocity (v\,) of a body traveling along circular orbit can be computed as:
v=\sqrt{\mu\over{r}}
where: Conclusion:
  • Velocity is constant along the path.

Orbital period

Under standard assumptions the orbital period (T\,\!) of a body traveling along circular orbit can be computed as:
T={2\pi\over{\sqrt{\mu}}}r^{3\over{2}}
where: Conclusions:

Energy

Under standard assumptions, specific orbital energy (\epsilon\,) is negative and the orbital energy conservation equation for this orbit takes the form:
{v^2\over{2}}-{\mu\over{r}}=-{\mu\over{2r}}=\epsilon< 0\,\!
where: The virial theorem applies even without taking a time-average:
  • the potential energy of the system is equal to twice the total energy
  • the kinetic energy of the system is equal to minus the total energy
Thus the escape velocity from any distance is √2 times the speed in a circular orbit at that distance: the kinetic energy is twice as much, hence the total energy is zero.

Equation of motion

Under standard assumptions, the orbital equation becomes:
r=
where:

Delta-v to reach a circular orbit

Maneuvering into a large circular orbit, e.g. a geostationary orbit, requires a larger delta-v than an escape orbit, although the latter implies getting arbitrarily far away and having more energy than needed for the orbital speed of the circular orbit. It is also a matter of maneuvering into the orbit. See also Hohmann transfer orbit.

See also

 

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