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Exact Trigonometric ConstantsExact constant expressions for trigonometric expressions are sometimes useful, mainly for simplifying solutions into radical forms which allow further simplification. All values of sine, cosine, and tangent of angles with 3° increments are derivable using identities: Half-angle, Double-angle, Addition/subtraction and values for 0°, 30°, 36° and 45°. Note that 1° = π/180 radians. Table of constants Values outside 0° ... 45° angle range are trivially extracted from circle axis reflection symmetry from these values. 0° Fundamental -
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3° - 60-sided polygon - sin(3°) = + √5)(1 − √3) + √2(√5 − 1)(√3 + 1)/16
- cos(3°) = + √5)(1 + √3) + √2(√5 − 1)(√3 − 1)/16
- tan(3°) = − √3)(3 + √5) − 2(2 − √(2(5 − √5)))/4
6° - 30-sided polygon - sin(6°) = − √5)) − (√5 + 1)/8
- cos(6°) = − √5)) + √3(√5 − 1)/8
- tan(6°) = − 2√5)(√5 + 1) + √3(1 − √5)/2
9° - 20-sided polygon - sin(9°) = − √5) + √2(√5 + 1)/8
- cos(9°) = − √5) + √2(√5 + 1)/8
- tan(9°) = −√(5 − 2√5)(2 + √5) + (√5 + 1)
12° - 15-sided polygon -
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15° - 12-sided polygon -
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18° - 10-sided polygon -
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21° - Sum 9° + 12° - sin(21°) = − √5)(√3 + 1) − √2(√3 − 1)(1 + √5)/16
- cos(21°) = − √5)(√3 − 1)+√2(√3 + 1)(1 + √5)/16
- tan(21°) = − 2√5)(1 + 2√3 − √5) + (2 + √3)(√5 − 3) + 2/2
22.5° - Octagon -
\sin \frac{\pi}{8} & = & \sin 22.5^\circ & = & \frac{\sqrt{2 - \sqrt{2}}}{2} \\ \cos \frac{\pi}{8} & = & \cos 22.5^\circ & = & \frac{\sqrt{2 + \sqrt{2}}}{2} \\ \tan \frac{\pi}{8} & = & \tan 22.5^\circ & = & \sqrt{2}-1 \\ \cot \frac{\pi}{8} & = & \cot 22.5^\circ & = & \sqrt{2}+1 \\ \end{matrix} 24° - Sum 12° + 12° - sin(24°) = √(2(5+√5))(1-√5)+2√3(1+√5))/16
- cos(24°) = √(6(5+√5))(√5-1)+2(1+√5))/16
- tan(24°) = (√(10+2√5)-2√3)(3+√5)/4
- cotan(24°) = (√(10+2√5)+2√3)(√5-1)/4
27° - Sum 12° + 15° - sin(27°) = ((2√(5+√5)+√2(1-√5))/8
- cos(27°) = ((2√(5+√5)+√2(√5-1))/8
- tan(27°) = -√(5-2(√5))+(√5-1)
30° - Hexagon -
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33° - Sum 15° + 18° - sin(33°) = (2√(5+√5)(-1+√3)+√2(√5-1)(1+√3))/16
- cos(33°) = (2√(5+√5)(+1+√3)+√2(√5-1)(1-√3))/16
- tan(33°) = (√(5(5-2√5))(-15+10√3-7√5+4√15)+5((-2+√3)(3+√5)+2))/10
36° - Pentagon -
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39° - Sum 18°+ 21° - sin(39°) = (2√(5-√5)(1-√3)+√2(+1+√3)(1+√5))/16
- cos(39°) = (2√(5-√5)(1+√3)+√2(-1+√3)(1+√5))/16
- tan(39°) = (√(2(5+√5))-2)((2-√3)(-3+√5)+2)/4
42° - Sum 21° + 21° - sin(42°) = (√(6(5-√5))(1+√5)+2(1-√5))/16
- cos(42°) = (√(2(5-√5))(1+√5)+2√3(-1+√5))/16
- tan(42°) = (-√(5-2√5)(3+√5)+√3(1+√5))/2
45° - Square -
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Notes Uses for constants As an example of the use of these constants, the volume of a dodecahedron is - V = 5e3cos(36°)/tan2(36°)
Using - cos(36°) = (√5 + 1)/4
- tan(36°) = √(5 − 2√5)
this can be simplified to: - V = e3(15 + 7√5)/4.
Derivation triangles The derivation of sine, cosine, and tangent constants into radial forms is based upon the constructability of right triangles. Here are right triangles made from symmetry sections of regular polygons are used to calculate fundamental trigonometric ratios. Each right triangle represents three points in a regular polygon: a vertex, an edge center containing that vertex, and the polygon center. A N-agon can be divided into 2N right triangle with angles of {180/N, 90−180/N, 90} degrees, for N = 3, 4, 5, ... Constructibility of 3, 4, 5, and 15 sided polygons are the basis, and angle bisectors allow multiples of two to also be derived. - Constructable
- 3×2X-sided regular polygons, X = 0, 1, 2, 3, ...
- 4×2X-sided
- 45°-45°-90° triangle - square (4-sided)
- 67.5°-22.5°-90° triangle - octagon (8-sided)
- 88.75°-11.25°-90° triangle - hexakaidecagon (16-sided)
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- 5×2X-sided
- 15×2X-sided
- ... (Higher constructable regular polygons don't make whole degree angles: 17, 51, 85, 255, 257...)
- Nonconstructable (with whole or half degree angles) - No finite radial forms for these triangle edge ratios are known.
Expressions not unique Simplifying nested radical expressions is nontrivial. The expressions here may not all be fully reduced. Example: -
4\sin 18^\circ = \sqrt{2(3 - \sqrt 5)} = \sqrt 5 - 1 It's not evident that this simplification is equivalent, and in general nested radicals can not be reduced. - In general this is reducible:
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\sqrt{a + b\sqrt c} = d + e\sqrt c , if a2 − 4b2c is a perfect square. See also External links
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